An electric dipole is placed in a uniform ele | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The torque $\vec{	au}$ on an electric dipole in a uniform electric field is given by $\vec{	au} = \vec{p} 	imes \vec{E}$.The magnitude of the t

Vedclass · Accepted Answer

$1.25 	imes 10^{-28}\ C\cdot m$

Vedclass · Answer

(A) The torque $\vec{	au}$ on an electric dipole in a uniform electric field is given by $\vec{	au} = \vec{p} 	imes \vec{E}$.The magnitude of the torque is $	au = pE \sin	heta$.From the graph,the maximum torque $	au_{	ext{max}}$ is $50 	imes 10^{-28}\ N\cdot m$ (at $	heta = 90^\circ$,where $\sin	heta = 1$).Thus,$	au_{	ext{max}} = pE$.Given $E = 40\ N/C$ and $	au_{	ext{max}} = 50 	imes 10^{-28}\ N\cdot m$:$50 	imes 10^{-28} = p 	imes 40$$p = \frac{50 	imes 10^{-28}}{40}$$p = 1.25 	imes 10^{-28}\ C\cdot m$.

An electric dipole is placed in a uniform electric field $\vec{E}$ of magnitude $40\ N/C$. The graph shows the magnitude of the torque $\tau$ on the dipole versus the angle $\theta$ between the field $\vec{E}$ and the dipole moment $\vec{p}$. The magnitude of the dipole moment $\vec{p}$ is equal to:

Similar Questions

An electric dipole has the magnitude of its charge as $q$ and its dipole moment is $p$. It is placed in a uniform electric field $E$. If its dipole moment is along the direction of the field,the force on it and its potential energy are respectively

What is the force acting on an electric dipole in a uniform electric field?

If the magnitude of the intensity of the electric field at a distance $x$ on the axial line and at a distance $y$ on the equatorial line for a given electric dipole are equal,then the ratio $x:y$ is:

An electric dipole is kept in a non-uniform electric field. It experiences

Four charges are placed at a distance $a$ from the origin as shown in the figure. The dipole moment of the configuration is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module